## Monday, October 20, 2014

### Problem of the year 5775

OK so it's 5775 according to the Hebrew calendar. Which means of course that it's Problem of the year time (well ok it's a bit late but so what).

5775 turns out to be kinda tough (or I'm being silly).

(5+7)/(7+5)=1 is pretty easy.
getting 5-sqrt(7+7-5)=2 took me quite a while.

I have at the time of writing no way to get 3.

5-(7/7)^5=4
5*((7/7)^5)=5
5+(7/7)^5=6

all sort of fit together.

7 like 3 I don't have yet, although I've spent less time on it.

5+sqrt(7+7-5)=8

5-(7/7)+5=9
5*(7/7)+5=10
5+(7/7)+5=11

again fit into a nice group.

This is about where I stopped thinking about these (because 3 and 7 where incomplete).

So naturally the point of this post is to see what people come up with for the 3,7 and things bigger than 11.  Enjoy!

#### 1 comment:

1. If you're allowed an initial minus then
sqrt((-5 + 7) * 7 - 5) = 3

5 + sqrt(7*7) - 5 = 7
sqrt((5+7)*(7+5)) = 12

5 + 7 + 7 - 5 = 14
5 * sqrt(7 + 7 - 5) = 15
sqrt(5! + (7/7)) + 5 = 16